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ORANGE EKSTRAKLASA
Dołączył: 26 Paź 2010
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 Wysłany: Śro 12:23, 19 Sty 2011 |
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Comprehensive examinations in 2005 in the \
15. A16.14O. 17.12O. 18. (1), see Figure 3 (2) slightly. 19. C2O. B \A (tips. From the known to be {5. Solve for {a ': substituted into the Jj}-f7}-1) 8, have Jj} = 3) 5. c6. c7. C8. C9. C (Tip: When the 5 dollars 3, the set 2 yuan Zhang, 1 yuan Zhang y,[link widoczny dla zalogowanych], there are + y = l8-5 × 3. Solve for {: 1,[link widoczny dla zalogowanych], when the 5 are 1. Element 2 , the set 2 yuan Zhang, l y-Zhang Yuan, there are + · 8-5 × 2. solve for t 5 dollars {:{:{ when the time sheets, set two yuan, Zhang, Zhang 1 per y , there are: l8-5 × 1. solve for the three kinds of coins in each case the total number of sheets not more than 1O Zhang, thus there are 7 different payment methods) 1O. B (Hint: bought a set before, with the y dollars, according to the meaning of problems too:: solve for) 【1.9 +1- I = y +1.5.11. B (Tip: Let bookstore accumulated Zhang was shown, the cost price of each sub-y, then each points, so y). And 3193:31 × lO3,[link widoczny dla zalogowanych], and 31 and 1O3 are prime, and each picture card cost less than 5 angle (ie 5O points), so = 1O3. Each cost 31 points,[link widoczny dla zalogowanych], or O. 31 yuan) 12. A (Note: easy to get three of the known age and for 84 years, thus rectifiable three aged 1O, 38,36, so the state of maximum and minimum required to open a {;. Solve for 18 =--, n.3Ol1D = a, n.15m +5 mouth ≤, foundation × 5, solve for ≥. so at least 4 to open the door to check on their votes within 5min), \on page 32) 1. D2. B3. c4. A5. A6. D7. B8. D9. {A 21O. A 1411. ③ 12.513_f_414.6115_2316.8lV = l17. . +41 Oo √. 41oo, or 25 a ÷. -. ', Y is a positive integer, should be a multiple of 4. . -. When Lu 4:00, 18; when Pina time, l1; as 12:00. Therefore, positive integer solution of equation (; (: i; ('18 .- 7, 【'a 14.19. Dualistic equation from the definition of j have a 8 = 1, +3 ≠ o) l-1 = 1. (n a 2 ≠ o) a solution was fm., 20.r +, good +1 = O.21_3 +5 (+ y): 36, ① 34 (+ = 36, ② a solution: ① + ②, too 3 (+9 () _72, that is, 6. to +,, = 6 was substituted into ① +6 × 5:36 ..·.: 2. the thirty six substitute ② 3y +4 × 6 = 36 .. · .4. . *. the original equations with the solutions of the equations was bare {pen: a ③ ④ × 2 curse was 936.4.
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