New calculation method for shaft strength _298

ncycgdxhl

,[link widoczny dla zalogowanych]
New calculation method for shaft strength

(> A z) is also available in the z axis plane of the moment equation and torque equation:. £ M () = Σ a-Σ . Report of a JI a + Z. M ( a )' 0 ...,. \(7) ( Cool

loop 3 as shown in Figure 3, the stepped shaft, any ~ bending section modulus section Ⅳ) singular functions can also be expressed as: r () = W. + Σ (one by one) <a King \(1o) 3 axis of the strength calculation. According to (7), ( Cool

, (9) 5t ~ (1o) 5t, calculate the surface of the third shaft of any part of it very stress strength theory Joel. (Z) died √) a hatch) + Er (z (11) to solve the following one-dimensional optimization problem: rain, (z) one by one ()]·· CI = a ≤ o} (121C2 eleven £ ≤ 0J: the location of the dangerous section of Portland. and dangerous section of maximum stress on the plant ‰ _ one by one (.), then press the edge of the shaft of the strength of the school: ... a 2 shaft Chen Yurong new method of strength calculation ‰ ≤ [] (13) if solid shaft diameter of any cross section (), the bending section modulus) =. (x) / 32. the () expression on behalf of the people (11), and make it equal to the allowable stress Ea], can be : s plant - a ---==-- two hundred twenty-two thousand two hundred twenty-two == d () a √ √ )+()+ relentless j (14) on the strength of such type is the function of the shaft diameter can be used as determine the part of the shaft design basis. If the shaft diameter by such design can be modeled (12), by solving the following mathematical model: raing () one by one (), s. t. C =-- X ≤ 0 (13) C2 ≤ 0J one by one to determine the shaft diameter: d - d (xo) one by one g (.) (16) 4 program design and calculation method of the above examples, I use the Rasi ~ a common language program STR. By any concentration of power, concentrated force couple and uniform, with an arbitrary shape of the shaft ladder, as long as in Figure 2 and Figure 3 shows the rules for the preparation of data starting STR. The results can be obtained quickly. On the shaft, spindle and non-circular section beam, but also use the program as a special case STR. Example: Figure 4 (a) shows stepped shaft, the force in Figure 4 (b) below. Requirements: (1) material allowable stress [mouth] of a 65MPa, checking strength; (2) determine the terms of equal diameter circle by the diameter of shaft 2, the rules shown in Figure 3, the shaft in the. ry plane suffered power P [163,978, a 2414,1273, force location is d-Eo, 65,145,2 z53 '; XZ plane suffered power P = E4268, a 2686, a 6632,5 oso], The role of force position A = A; shaft torque suffered = Ez68.6, a 268.6], Torque position E a [6s, 145]; shaft diameter d: 『4O, 55,65,8 l, 4Q4O] Ding, ladder position X a [maggots, 9O, 105,185,213.5,225 D T. Start the program with the above data STR, can be: (1) ... a, (41): 27.87MPa% Eo] = 65MPa, therefore the strength of the shaft is sufficient; (2) d - d (145) = 42. 67mm. Figure 4 (c) and Figure 4 (d) shows the shaft of the radius of the stress intensity curves and other curves. 5 Conclusion Using singularity functions, the stress will not be written in a single continuous expression, and then optimize the method to determine the dangerous section, you can not draw the bending moment diagram and torque graph for the case of the shaft or section design strength check . Based on this method for compiling a computer program, on the subject to different loads and geometry of the ladder with different axes of generality. * 36 Tianjin Light Industry College supervisor in April 1999 lI! I0 Good {Good {i65 『80Js. JiIf4268NY ~ ... puzzle 2,278,742.67. I) lMP b} - 1 \ d {) (tam) - \ Wai 4